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Force behind a tank shell12/23/2023 ![]() ![]() This can therefore be calculated by subtracting negative 20 from 285. We are interested in the relative velocity as we want the kinetic energy of the shell relative to the motion of the tank. The tank is moving with velocity 20 meters per second toward the cannon. This is the same as dividing 72 by 3.6, giving us an answer of 20. We can therefore multiply 72 by 1000 over 3600. We know there are 1000 meters in one kilometer and 3600 seconds in one hour. Our first step is therefore to convert 72 kilometers per hour into meters per second. Using these units gives us a kinetic energy in joules. The standard units of mass are kilograms and the standard units of velocity are meters per second. ![]() And we know that this can be calculated using the formula a half □□ squared, where □ is the mass and □ is the velocity. The tank is moving in the opposite direction, at a velocity of 72 kilometers per hour. The shell has a mass of 16 kilograms and is traveling at a velocity of 285 meters per second. We are told that a cannon fires a shell toward a tank that was moving towards it. Let’s begin this question by modeling the situation. Determine the kinetic energy of the shell relative to the motion of the tank. ![]() A cannon fired a shell of mass 16 kilograms at 285 meters per second toward a tank that was moving at 72 kilometers per hour in a straight line directly toward the cannon. ![]()
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